Integrand size = 40, antiderivative size = 233 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\left (\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) x\right )-\frac {\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \log (\sin (c+d x))}{d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d} \]
[Out]
Time = 0.70 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.175, Rules used = {3713, 3686, 3716, 3709, 3610, 3612, 3556} \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\frac {a \left (5 a^2 B-15 a b C-12 b^2 B\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (5 a C+7 b B) \cot ^4(c+d x)}{20 d}+\frac {\left (a^3 C+3 a^2 b B-3 a b^2 C-b^3 B\right ) \cot ^2(c+d x)}{2 d}-\frac {\left (a^3 B-3 a^2 b C-3 a b^2 B+b^3 C\right ) \cot (c+d x)}{d}+\frac {\left (a^3 C+3 a^2 b B-3 a b^2 C-b^3 B\right ) \log (\sin (c+d x))}{d}-x \left (a^3 B-3 a^2 b C-3 a b^2 B+b^3 C\right )-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d} \]
[In]
[Out]
Rule 3556
Rule 3610
Rule 3612
Rule 3686
Rule 3709
Rule 3713
Rule 3716
Rubi steps \begin{align*} \text {integral}& = \int \cot ^6(c+d x) (a+b \tan (c+d x))^3 (B+C \tan (c+d x)) \, dx \\ & = -\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac {1}{5} \int \cot ^5(c+d x) (a+b \tan (c+d x)) \left (a (7 b B+5 a C)-5 \left (a^2 B-b^2 B-2 a b C\right ) \tan (c+d x)-b (3 a B-5 b C) \tan ^2(c+d x)\right ) \, dx \\ & = -\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac {1}{5} \int \cot ^4(c+d x) \left (-a \left (5 a^2 B-12 b^2 B-15 a b C\right )-5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \tan (c+d x)-b^2 (3 a B-5 b C) \tan ^2(c+d x)\right ) \, dx \\ & = \frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac {1}{5} \int \cot ^3(c+d x) \left (-5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right )+5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \tan (c+d x)\right ) \, dx \\ & = \frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac {1}{5} \int \cot ^2(c+d x) \left (5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right )+5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \tan (c+d x)\right ) \, dx \\ & = -\frac {\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac {1}{5} \int \cot (c+d x) \left (5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right )-5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \tan (c+d x)\right ) \, dx \\ & = -\left (\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) x\right )-\frac {\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \int \cot (c+d x) \, dx \\ & = -\left (\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) x\right )-\frac {\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac {a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac {a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}+\frac {\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \log (\sin (c+d x))}{d}-\frac {a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 1.24 (sec) , antiderivative size = 237, normalized size of antiderivative = 1.02 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\frac {-60 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)+30 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)+20 a \left (a^2 B-3 b^2 B-3 a b C\right ) \cot ^3(c+d x)-15 a^2 (3 b B+a C) \cot ^4(c+d x)-12 a^3 B \cot ^5(c+d x)+30 i (a+i b)^3 (B+i C) \log (i-\tan (c+d x))+60 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \log (\tan (c+d x))+30 (i a+b)^3 (B-i C) \log (i+\tan (c+d x))}{60 d} \]
[In]
[Out]
Time = 0.36 (sec) , antiderivative size = 243, normalized size of antiderivative = 1.04
method | result | size |
parallelrisch | \(\frac {\left (-90 B \,a^{2} b +30 B \,b^{3}-30 C \,a^{3}+90 C a \,b^{2}\right ) \ln \left (\sec \left (d x +c \right )^{2}\right )+\left (180 B \,a^{2} b -60 B \,b^{3}+60 C \,a^{3}-180 C a \,b^{2}\right ) \ln \left (\tan \left (d x +c \right )\right )-12 B \,a^{3} \cot \left (d x +c \right )^{5}+\left (-45 B \,a^{2} b -15 C \,a^{3}\right ) \cot \left (d x +c \right )^{4}+20 a \cot \left (d x +c \right )^{3} \left (B \,a^{2}-3 B \,b^{2}-3 C a b \right )+\left (90 B \,a^{2} b -30 B \,b^{3}+30 C \,a^{3}-90 C a \,b^{2}\right ) \cot \left (d x +c \right )^{2}+\left (-60 B \,a^{3}+180 B a \,b^{2}+180 C \,a^{2} b -60 C \,b^{3}\right ) \cot \left (d x +c \right )-60 d x \left (B \,a^{3}-3 B a \,b^{2}-3 C \,a^{2} b +C \,b^{3}\right )}{60 d}\) | \(243\) |
derivativedivides | \(\frac {-\frac {-3 B \,a^{2} b +B \,b^{3}-C \,a^{3}+3 C a \,b^{2}}{2 \tan \left (d x +c \right )^{2}}+\left (3 B \,a^{2} b -B \,b^{3}+C \,a^{3}-3 C a \,b^{2}\right ) \ln \left (\tan \left (d x +c \right )\right )-\frac {B \,a^{3}-3 B a \,b^{2}-3 C \,a^{2} b +C \,b^{3}}{\tan \left (d x +c \right )}-\frac {B \,a^{3}}{5 \tan \left (d x +c \right )^{5}}-\frac {a^{2} \left (3 B b +C a \right )}{4 \tan \left (d x +c \right )^{4}}+\frac {a \left (B \,a^{2}-3 B \,b^{2}-3 C a b \right )}{3 \tan \left (d x +c \right )^{3}}+\frac {\left (-3 B \,a^{2} b +B \,b^{3}-C \,a^{3}+3 C a \,b^{2}\right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+\left (-B \,a^{3}+3 B a \,b^{2}+3 C \,a^{2} b -C \,b^{3}\right ) \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(248\) |
default | \(\frac {-\frac {-3 B \,a^{2} b +B \,b^{3}-C \,a^{3}+3 C a \,b^{2}}{2 \tan \left (d x +c \right )^{2}}+\left (3 B \,a^{2} b -B \,b^{3}+C \,a^{3}-3 C a \,b^{2}\right ) \ln \left (\tan \left (d x +c \right )\right )-\frac {B \,a^{3}-3 B a \,b^{2}-3 C \,a^{2} b +C \,b^{3}}{\tan \left (d x +c \right )}-\frac {B \,a^{3}}{5 \tan \left (d x +c \right )^{5}}-\frac {a^{2} \left (3 B b +C a \right )}{4 \tan \left (d x +c \right )^{4}}+\frac {a \left (B \,a^{2}-3 B \,b^{2}-3 C a b \right )}{3 \tan \left (d x +c \right )^{3}}+\frac {\left (-3 B \,a^{2} b +B \,b^{3}-C \,a^{3}+3 C a \,b^{2}\right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+\left (-B \,a^{3}+3 B a \,b^{2}+3 C \,a^{2} b -C \,b^{3}\right ) \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(248\) |
norman | \(\frac {\left (-B \,a^{3}+3 B a \,b^{2}+3 C \,a^{2} b -C \,b^{3}\right ) x \tan \left (d x +c \right )^{6}+\frac {\left (3 B \,a^{2} b -B \,b^{3}+C \,a^{3}-3 C a \,b^{2}\right ) \tan \left (d x +c \right )^{4}}{2 d}-\frac {\left (B \,a^{3}-3 B a \,b^{2}-3 C \,a^{2} b +C \,b^{3}\right ) \tan \left (d x +c \right )^{5}}{d}-\frac {B \,a^{3} \tan \left (d x +c \right )}{5 d}+\frac {a \left (B \,a^{2}-3 B \,b^{2}-3 C a b \right ) \tan \left (d x +c \right )^{3}}{3 d}-\frac {a^{2} \left (3 B b +C a \right ) \tan \left (d x +c \right )^{2}}{4 d}}{\tan \left (d x +c \right )^{6}}+\frac {\left (3 B \,a^{2} b -B \,b^{3}+C \,a^{3}-3 C a \,b^{2}\right ) \ln \left (\tan \left (d x +c \right )\right )}{d}-\frac {\left (3 B \,a^{2} b -B \,b^{3}+C \,a^{3}-3 C a \,b^{2}\right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2 d}\) | \(275\) |
risch | \(-B \,a^{3} x +3 B a \,b^{2} x +3 C \,a^{2} b x -C \,b^{3} x -\frac {6 i B \,a^{2} b c}{d}-\frac {2 i \left (-60 C \,a^{2} b -60 B a \,b^{2}+15 C \,b^{3}+23 B \,a^{3}-70 B \,a^{3} {\mathrm e}^{2 i \left (d x +c \right )}-60 C \,b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-45 i C a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+180 i B \,a^{2} b \,{\mathrm e}^{6 i \left (d x +c \right )}-135 i C a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-180 i B \,a^{2} b \,{\mathrm e}^{4 i \left (d x +c \right )}+135 i C a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+90 i B \,a^{2} b \,{\mathrm e}^{2 i \left (d x +c \right )}-90 i B \,a^{2} b \,{\mathrm e}^{8 i \left (d x +c \right )}+45 i C a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+90 C \,b^{3} {\mathrm e}^{4 i \left (d x +c \right )}-90 B \,a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+45 B \,a^{3} {\mathrm e}^{8 i \left (d x +c \right )}+15 C \,b^{3} {\mathrm e}^{8 i \left (d x +c \right )}-60 C \,b^{3} {\mathrm e}^{6 i \left (d x +c \right )}+140 B \,a^{3} {\mathrm e}^{4 i \left (d x +c \right )}-90 C \,a^{2} b \,{\mathrm e}^{8 i \left (d x +c \right )}+270 B a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+270 C \,a^{2} b \,{\mathrm e}^{6 i \left (d x +c \right )}-330 B a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-330 C \,a^{2} b \,{\mathrm e}^{4 i \left (d x +c \right )}+210 B a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+210 C \,a^{2} b \,{\mathrm e}^{2 i \left (d x +c \right )}-60 i C \,a^{3} {\mathrm e}^{4 i \left (d x +c \right )}-15 i B \,b^{3} {\mathrm e}^{2 i \left (d x +c \right )}+30 i C \,a^{3} {\mathrm e}^{2 i \left (d x +c \right )}-90 B a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+15 i B \,b^{3} {\mathrm e}^{8 i \left (d x +c \right )}-30 i C \,a^{3} {\mathrm e}^{8 i \left (d x +c \right )}-45 i B \,b^{3} {\mathrm e}^{6 i \left (d x +c \right )}+60 i C \,a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+45 i B \,b^{3} {\mathrm e}^{4 i \left (d x +c \right )}\right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}+i B \,b^{3} x -i C \,a^{3} x +\frac {6 i C a \,b^{2} c}{d}+\frac {2 i B \,b^{3} c}{d}-\frac {2 i C \,a^{3} c}{d}+3 i C a \,b^{2} x -3 i B \,a^{2} b x +\frac {3 a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) B b}{d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) B \,b^{3}}{d}+\frac {a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) C}{d}-\frac {3 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) C a \,b^{2}}{d}\) | \(755\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 266, normalized size of antiderivative = 1.14 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\frac {30 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\frac {\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{5} + 15 \, {\left (3 \, C a^{3} + 9 \, B a^{2} b - 6 \, C a b^{2} - 2 \, B b^{3} - 4 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} d x\right )} \tan \left (d x + c\right )^{5} - 60 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} \tan \left (d x + c\right )^{4} - 12 \, B a^{3} + 30 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \tan \left (d x + c\right )^{3} + 20 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2}\right )} \tan \left (d x + c\right )^{2} - 15 \, {\left (C a^{3} + 3 \, B a^{2} b\right )} \tan \left (d x + c\right )}{60 \, d \tan \left (d x + c\right )^{5}} \]
[In]
[Out]
Time = 12.36 (sec) , antiderivative size = 462, normalized size of antiderivative = 1.98 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\begin {cases} \text {NaN} & \text {for}\: c = 0 \wedge d = 0 \\x \left (a + b \tan {\left (c \right )}\right )^{3} \left (B \tan {\left (c \right )} + C \tan ^{2}{\left (c \right )}\right ) \cot ^{7}{\left (c \right )} & \text {for}\: d = 0 \\\text {NaN} & \text {for}\: c = - d x \\- B a^{3} x - \frac {B a^{3}}{d \tan {\left (c + d x \right )}} + \frac {B a^{3}}{3 d \tan ^{3}{\left (c + d x \right )}} - \frac {B a^{3}}{5 d \tan ^{5}{\left (c + d x \right )}} - \frac {3 B a^{2} b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac {3 B a^{2} b \log {\left (\tan {\left (c + d x \right )} \right )}}{d} + \frac {3 B a^{2} b}{2 d \tan ^{2}{\left (c + d x \right )}} - \frac {3 B a^{2} b}{4 d \tan ^{4}{\left (c + d x \right )}} + 3 B a b^{2} x + \frac {3 B a b^{2}}{d \tan {\left (c + d x \right )}} - \frac {B a b^{2}}{d \tan ^{3}{\left (c + d x \right )}} + \frac {B b^{3} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac {B b^{3} \log {\left (\tan {\left (c + d x \right )} \right )}}{d} - \frac {B b^{3}}{2 d \tan ^{2}{\left (c + d x \right )}} - \frac {C a^{3} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac {C a^{3} \log {\left (\tan {\left (c + d x \right )} \right )}}{d} + \frac {C a^{3}}{2 d \tan ^{2}{\left (c + d x \right )}} - \frac {C a^{3}}{4 d \tan ^{4}{\left (c + d x \right )}} + 3 C a^{2} b x + \frac {3 C a^{2} b}{d \tan {\left (c + d x \right )}} - \frac {C a^{2} b}{d \tan ^{3}{\left (c + d x \right )}} + \frac {3 C a b^{2} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac {3 C a b^{2} \log {\left (\tan {\left (c + d x \right )} \right )}}{d} - \frac {3 C a b^{2}}{2 d \tan ^{2}{\left (c + d x \right )}} - C b^{3} x - \frac {C b^{3}}{d \tan {\left (c + d x \right )}} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.38 (sec) , antiderivative size = 250, normalized size of antiderivative = 1.07 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {60 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} {\left (d x + c\right )} + 30 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 60 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac {60 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} \tan \left (d x + c\right )^{4} + 12 \, B a^{3} - 30 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \tan \left (d x + c\right )^{3} - 20 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2}\right )} \tan \left (d x + c\right )^{2} + 15 \, {\left (C a^{3} + 3 \, B a^{2} b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{5}}}{60 \, d} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 670 vs. \(2 (225) = 450\).
Time = 1.57 (sec) , antiderivative size = 670, normalized size of antiderivative = 2.88 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\frac {6 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 15 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 45 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 70 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, C a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 180 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 540 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 360 \, C a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 120 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 660 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1800 \, C a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1800 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 480 \, C b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 960 \, {\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} {\left (d x + c\right )} - 960 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right ) + 960 \, {\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) - \frac {2192 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6576 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 6576 \, C a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 2192 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 660 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 1800 \, C a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 1800 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 480 \, C b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 180 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 540 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 360 \, C a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 70 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 120 \, C a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 120 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 15 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 45 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, B a^{3}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{960 \, d} \]
[In]
[Out]
Time = 8.43 (sec) , antiderivative size = 238, normalized size of antiderivative = 1.02 \[ \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {{\mathrm {cot}\left (c+d\,x\right )}^5\,\left (\mathrm {tan}\left (c+d\,x\right )\,\left (\frac {C\,a^3}{4}+\frac {3\,B\,b\,a^2}{4}\right )+\frac {B\,a^3}{5}+{\mathrm {tan}\left (c+d\,x\right )}^2\,\left (-\frac {B\,a^3}{3}+C\,a^2\,b+B\,a\,b^2\right )+{\mathrm {tan}\left (c+d\,x\right )}^4\,\left (B\,a^3-3\,C\,a^2\,b-3\,B\,a\,b^2+C\,b^3\right )+{\mathrm {tan}\left (c+d\,x\right )}^3\,\left (-\frac {C\,a^3}{2}-\frac {3\,B\,a^2\,b}{2}+\frac {3\,C\,a\,b^2}{2}+\frac {B\,b^3}{2}\right )\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,\left (-C\,a^3-3\,B\,a^2\,b+3\,C\,a\,b^2+B\,b^3\right )}{d}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (B+C\,1{}\mathrm {i}\right )\,{\left (a+b\,1{}\mathrm {i}\right )}^3\,1{}\mathrm {i}}{2\,d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (B-C\,1{}\mathrm {i}\right )\,{\left (a-b\,1{}\mathrm {i}\right )}^3\,1{}\mathrm {i}}{2\,d} \]
[In]
[Out]